Two identical charges, 5 µC each are fixed at a distance 8 cm and a charged particle of mass 9 × 10 -6 kg and charge – 10 µC is placed at a distance 5 cm from each of them and is released. Find the speed of the particle when it is nearest to the two charges.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(10 3 m/s)
Sol.
By C.O.M.E., U p + K p = K c + U c
⇒ q 
+ 0 = 
or 
= 2 K q 0 q 
× v 2 = 2 × 9 × 10 9 × 5 × 10 –6 × 10 × 10 –6 × 5.
or v 2 = 4 × 25 × 10 4 .
∴ v = 1000 m/sec.
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